86(5x^2)=4

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Solution for 86(5x^2)=4 equation:



86(5x^2)=4
We move all terms to the left:
86(5x^2)-(4)=0
a = 865; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·865·(-4)
Δ = 13840
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{13840}=\sqrt{16*865}=\sqrt{16}*\sqrt{865}=4\sqrt{865}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{865}}{2*865}=\frac{0-4\sqrt{865}}{1730} =-\frac{4\sqrt{865}}{1730} =-\frac{2\sqrt{865}}{865} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{865}}{2*865}=\frac{0+4\sqrt{865}}{1730} =\frac{4\sqrt{865}}{1730} =\frac{2\sqrt{865}}{865} $

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